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Re: Altitude-less Azimuth formula?
From: Tony Oz
Date: 2019 Nov 10, 14:09 -0800
From: Tony Oz
Date: 2019 Nov 10, 14:09 -0800
As a follow-up: looks like it is indeed valid, it is a re-arranged Robin Stuart's Pol() formula.
A calculator I dug it from was an RPN one lacking both Pol() and arctan2() functions.
Regards,
Tony
60°N 30°E