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Re: Azimuth computation formula in Pub. 229
From: Rafael C. Caruso
Date: 2021 Jan 17, 09:35 -0800
From: Rafael C. Caruso
Date: 2021 Jan 17, 09:35 -0800
Hello Lars,
Many thanks for sending me the derivation - this was exactly what I was looking for. I had assumed it involved dividing an expression for sin Z by an expresssion for cos Z, but had not made much headway. Once again, a derivation always seems straightforward when you see it done by someone who knows what he is doing!
Kind regards,
Rafael
