NavList:

This is my thinking about this problem so far.  With no time and date given, we must be looking for a free gift from this particular shot in a similar way that a meridian passage or a shot from the North or South Pole turns the celestial triangle into a straight-line problem.  The gift here must be that on this date and time the Milky Way (MW) appears almost horizontal.  In other words, the observer’s horizon lies in our Galactic Plane.  Therefore, if we can find the angle between our Celestial Plane and our Galactic Plane, and if we can assess how high the MW lies above the observer’s horizon from the photograph, we might be in business.  The angle between our Celestial Plane and the Galactic Plane has been published as 63 degrees.   Playing around with ideas.  If I was at 63 degrees north or south, the Milky Way would be above my head.  Guessing at it being around 30 degrees in the photograph, I need to travel about 60 degrees south or north for the MW to be at 30 degrees, so I must be at about 3 degrees north or south.  However, I appear to be completely wrong.  Dave P