Welcome to the NavList Message Boards.

NavList:

A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding

Compose Your Message

Message:αβγ
Message:abc
Add Images & Files
    Name or NavList Code:
    Email:
       
    Reply
    Re: Longitude by unequal altitudes - Brent
    From: Lars Bergman
    Date: 2020 Jul 7, 08:08 -0700

    David, you should not be totally confused. The last term's numerator is clearly 620 seconds of arc, the altitude difference. In the denominator you have a constant of 2, times C which is given as 1.54 (seconds of arc)/(minutes of time)2, times (I-g) given as 77.5 minutes of time. Now 620 / (2·1.54·77.5) = 2.60 and the dimension becomes minutes of time, or 2m36s. I guess there is an explanation somewhere in Brent of the dimension of C as given in Table III.

    Lars

       
    Reply
    Browse Files

    Drop Files

    NavList

    What is NavList?

    Get a NavList ID Code

    Name:
    (please, no nicknames or handles)
    Email:
    Do you want to receive all group messages by email?
    Yes No

    A NavList ID Code guarantees your identity in NavList posts and allows faster posting of messages.

    Retrieve a NavList ID Code

    Enter the email address associated with your NavList messages. Your NavList code will be emailed to you immediately.
    Email:

    Email Settings

    NavList ID Code:

    Custom Index

    Subject:
    Author:
    Start date: (yyyymm dd)
    End date: (yyyymm dd)

    Visit this site
    Visit this site
    Visit this site
    Visit this site
    Visit this site
    Visit this site