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    Re: Lunar Halo
    From: Igor S.
    Date: 2019 Sep 16, 06:28 -0700
    I slightly edited your photo and from that I determined roughly the angular radius of halo (see attached pdf). 
    SD_moon = 16'  (approx.)
    R = 8.5*(2*SD_moon)/60' = 4.5 degree which is considerably less than 22 degree. Was it a moon corona ( https://en.wikipedia.org/wiki/Corona_(optical_phenomenon) ) or moon halo ( https://en.wikipedia.org/wiki/22%C2%B0_halo )?
    kind regards,
    Igor
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    Lunar_halo.pdf
       
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