NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Robin Stuart
Date: 2025 Dec 7, 06:45 -0800
Recently Lars Bergman and I spent some time digesting formulas given in the HMNAO Compact Data publication that Lars has in his possession. After a few false starts we were able to derive all the formulas that appear in the attached scan. The publication states "If three or more position lines are obtained an estimate of the error in position may be calculated".
The recent discussion on the thin triangle can serve to demonstrate the use of these formulas with the results summarized below
Offsets 11.1NM North, 20.5 East
(Note that because the distance to the offset point is greater than 20NM it is advised to repeat the calculation centred on the offset point but as Frank instructs us "don't worry about longitude scaling" this can be avoided.)
Here's a summary of further results for the thin triangle
Estimated position error, σ : 1.89NM
Standard deviation in longitude σL : 1.69NM (this is more accurately described as standard deviation in departure).
Standard deviation in latitude σB : 1.58NM
95% Confidence ellipse has
Semi-major axis : 4.64 NM
Semi-minor axis : 3.25 NM in the direction of 39.2° azimuth
Using the results obtained in my Journal of Navigation paper Probabilities in a Gaussian Cocked Hat (https://doi.org/10.1017/S0373463319000110) and assuming a gaussian error distribution with standard deviation σ as above, the probability that the thin triangle encloses the observer's true position is 34.7%.
I attach a spreadsheet that computes the quantities described here.
Robin Stuart






