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Re: Time of Spring
From: Paul Hirose
Date: 2018 Mar 21, 22:27 -0700
From: Paul Hirose
Date: 2018 Mar 21, 22:27 -0700
On 2018-03-20 20:15, Terry Syrokosz wrote: > Spring occured at 16:17:19.333... GMT 03/20/18 On 2018-03-21 8:30, Dave Walden wrote: >From JPL, I make it: > 16:15:21.750...UTC I put the equinox (the conventional beginning of spring) at 16:15:27 UTC. In chronological order: 16:15:20 UTC zero right ascension 16:15:27 UTC zero ecliptic longitude 16:16:04 UTC zero declination 16:16:24 UTC zero ITRS latitude The second line (zero longitude) is the formal definition of the equinox. If the Sun were exactly on the ecliptic the first three phenomena would occur at the same instant. However, the Sun oscillates north and south of the ecliptic on a monthly cycle. At this equinox its ecliptic latitude is -.7″. By happenstance that's practically the southern peak of the oscillation. The last line is the layman's definition of the equinox. For most people that's close enough, and avoids an explanation of ecliptic coordinates. Zero ITRS latitude does not coincide with zero declination because Earth's axis of rotation (the basis of the celestial equator) is a few tens of feet from the ITRS (geodetic) pole. Therefore the planes of the celestial and geodetic equators fail to coincide by a few tenths of an arc second. My computations of the Sun's geocentric apparent place utilzed the JPL DE431 ephemeris, IAU 2006 precession, and 2000B nutation models. Pole x = 0.0036″, y = 0.3775″ (these affect only the time of zero ITRS latitude). The JPL Horizons online calculator says zero ecliptic longitude occurs about 1.5 seconds after my time. That's due to a difference in precession / nutation models. To duplicate the Horizons values, 1) do NOT apply frame bias, 2) use the IAU 1976 precession and 1980 nutation models, 3) to the nutation angles add the celestial pole offsets dEps1980 and dPsi1980 published by the IERS.