NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Andrés Ruiz
Date: 2010 Dec 17, 11:44 +0100
Antoine wrote:
2 - If we assume that both your position and your
Observed Sextant values are correct, then your UT would have been 14h41m16.5s ,
(or LT = 8h41m16.5s), which translates into a difference of 2m29.5s (+6h)
between UT and Watch.
…
Could you be wrong with the time UT/LT? At 14:43:46
the Sun is not be seen at Diego Garcia!
Here is my solution.
The input file is added. The solution is:
12/12/2010
08:43:46 UT1
Geocentric equatorial
coordinates
Moon:
GHA = 234.950673 º = 234º
57.0'
Dec = -4.529893 º = -4º
31.8'
Phase: 39% (+)
Sun:
GHA = 312.539490 º = 312º 32.4'
Dec = -23.076579 º = -23º 4.6'
Geocentric lunar distance
LD = 76.816700 º = +76º 49'
0.1"
DR:
B = -7.271667 = -7º 16.3'
L = 72.446667 = 72º 26.8'
IE = -1.200000 '
air T =
air P = 1010.0 hPa
h Eye =
Dip = 0.166733
Time by lunar distances
Moon:
Hs = 37.115425 = 37º 6.9'
Limb = 0
SD = 14.798223 '
HP = 54.308845 '
R = 0.021554 º
OB = -0.000037 º
PA = 0.723512 º
AG = 0.002363 º
SDag = 14.940022 '
Sun:
Hs = 61.451472 = 61º 27.1'
Limb = 0
SD = 16.243914 '
HP = 0.148858 '
R = 0.008882 º
OB = 0.000001 º
PA = 0.001194 º
AG = 0.000010 º
SDag = 16.244531 '
Lunar observation:
LDs = 76.966667 = 76º 58.0'
Moon Limb = 1
body Limb = 1
Clearing Lunar Distance:
m = 36.928692 = 36º 55.7'
M = 37.630650375632321 =
37º 37.8'
s = 61.264739 = 61º 15.9'
S = 61.257050084970373 =
61º 15.4'
d = 77.466410 = 77º 28.0'
T1 = 7.000000 LD1 = 76.034602
Tc = 8.696442 LDo = 76.801740
T2 = 9.000000 LD2 = 76.939010
Error:
Ta = 08:43:46 LDc = 76º 49.0'
Tc
= 08:41:47 LDo = 76º 48.1'
Tc = 08:41:47 LDc = 76º 48.1'
|LDo-LDc(Ta)| = 0.014960º = 0.897612'
|LDo-LDc(Tc)| = 0.000040º = 0.002397'
|Ta-Tc| = 1.980155 min = 118.809318 s
Regards,
--
Andrés Ruiz
Navigational Algorithms
http://sites.google.com/site/navigationalalgorithms/