NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Emergency sun declination
From: Ken Gebhart
Date: 2004 May 19, 21:25 -0500
From: Ken Gebhart
Date: 2004 May 19, 21:25 -0500
on 5/19/04 4:37 PM, Jim Thompson at jim2@JIMTHOMPSON.NET wrote: > What about this method for emergency calcuation of declination? > > 1. Label a compass rose June 22 at 000o, Sept 23 at 090o, Dec 22 at 180o and > March 21 at 270o. > 2. The radius on the vertical axis is the declination of the sun. A > horizontal line from any date around the circle intersects that vertical > radius. > 3. Measure the length of the vertical axis from the center to the > intersection of the horizontal line, divide that length by the full radius, > and multiply that ratio by 22.5o. > 4. Error is +/- 0.5o. > > Jim Thompson > jim2@jimthompson.net > www.jimthompson.net > Outgoing mail scanned by Norton Antivirus > ----------------------------------------- > I am not sure I understand what Jim is saying, but here is what I have been preaching for many years. I would very much appreciate someone telling me if I am wrong, and if so, how much wrong! I tell people to take a piece of paper and draw horizontal lines, each separated by an equal amount. Label them +30, +20,+10,0,-10,-20,-30. Draw a circle centered on the 0 line so that the top of the circle is on 23.5, and the bottom is on -23.5. Label the cardinal points June 21, Sept 23, Dec 22, and March 21. Then I tell them to fill in the dates around the circle (easier said than done), and read the declination directly. I am guessing that if the Earth were in a circular orbit around the sun instead of elliptical, then my analogue would be OK. Does the ellipticity of the orbit make this wrong? Ken Gebhart