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Dr. Kolbe, I hope you will excuse my ignorance. I can do celestial nav.
thanks to some instruction in the use of HO 249, and the electronic method
(calculator). Now...I know that normally what we seek in celestial nav., is
the GP of a body, the distance off, and the Zn to the body's GP.
Understanding that though, I can't grasp how to work it backwards. If we use
HO 249, enter those tables using the arguments, destination lat. and the
long. of dest. as the declination, we still need a corrected altitude (Hc).
I guess I can't grasp what you mean. Could you take the trouble to explain
this to me? Thank you.

Ed Kitchin
----- Original Message -----
From  "Dr. Geoffrey Kolbe" 
To: 
Sent: Monday, February 28, 2000 2:06 AM
Subject: Re: Figuring Course given Lat/Long of destination


> So long as your destination is no more than 6000 miles away, your "usual"
> celestial navigation sight reduction tables can be used to determine a
> Great Circle course by simply replacing the Geographical Position of the
> celestial body with the Lat/Long of the destination. (For Longitudes East,
> the GHA required for the tables will be 360 degrees minus the Longitude).
> Turn the handle to produce the azimuth bearing and this will be your Great
> Circle course!
>
> Yours aye,
>
> Geoffrey.
>

   

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