NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Dave Walden
Date: 2011 Aug 21, 10:43 -0700
using your values, I get:
vega- altair
-22° 47' 36.1350"
+18° 32' 40.1201"
vega-antares
-22° 47' 36.1317"
+18° 32' 40.1067"
altair-antares
-22° 47' 35.9896"
+18° 32' 40.1042"
From Xephem, for which I make no claims, only that it seemed to work, I got:
antares
16 30 9.43
-26 27 28.7
altair
19 51 23.14
8 54 5.4
vega
18 37 22.25
38 47 49.3
I hope I've made no typos. I'll check my other program tomorrow.
**************************************************
Dave,
When I compute the distances from the app. Moon position that you are
giving below to the three stars in question, I obtain results that
differ by up to 8" from the distances that you posted on 8/16 in your
"refraction-free" problem. Unless I am making a bad mistake in my
calculation, my star ephemeris must differ substantially from yours. I
find both alternatives equally disturbing. Would you please post the
positions of the three stars (whether geocentric or topocentric for the
solution - it does not matter.)
I obtained from MICA:
Altair 19 51 23.125 + 8 54 05.51
Antares 16 30 09.432 - 26 27 28.66
Vega 18 37 22.186 + 38 47 49.42
Thanks,
Herbert
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