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Sight Reduction Formula Question
From: FS
Date: 2005 Jan 7, 07:24 -0800
From: FS
Date: 2005 Jan 7, 07:24 -0800
In _Celestial for the Cruising Navigator_ by Merle Turner, the navigational triangle azimuth formula is given as: cos Z = (sin d - (sin L * sin H ))/(cos L * cos H) but Dutton's Navigation and Piloting gives the much simpler: sin Z = ( cos d * sin t ) / cos H They both seem to work. But there must be some reason that the longer one is better, right? Works in more cases? My goal is simplicity, using a basic scientific calculator. Thank you in advance for any help, Great Wizards. The space navigation stuff is fascinating, albeit "over my head"! __________________________________ Do you Yahoo!? Yahoo! Mail - now with 250MB free storage. Learn more. http://info.mail.yahoo.com/mail_250
