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A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Spherical trig
From: Bill B
Date: 2008 Aug 06, 04:06 -0400
From: Bill B
Date: 2008 Aug 06, 04:06 -0400
Bill wrote: > Reading through the Bowditch 1995 edition, Chapter 21 on Navigational > Mathematics, I was playing with the different equations in "Table 2115. > Formulas for solving oblique spherical triangles." > > The first case--a, b, C known--the formula to find B was as follows and > attached: > > sin B = (Sin C * sin b) / sin c > > Sin c is not stated as a known. Even if I solve for it and plug it in, it > does not seem to work. Nor does the sine of any known. > > Before we go down that path, I understand the usual cel nav formulas use > straight Lat and declination instead of the complementary angle as cos x = > sin (90-x) and vice versa. > > What am I missing here? Pushed send a bit early. Please hold until I can express my "frame of reference" confusion with concrete examples. Bill B. --~--~---------~--~----~------------~-------~--~----~ Navigation List archive: www.fer3.com/arc To post, email NavList@fer3.com To , email NavList-@fer3.com -~----------~----~----~----~------~----~------~--~---
