NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Tides by bearing of the moon
From: Brad Morris
Date: 2009 Apr 8, 17:23 -0400
From: Brad Morris
Date: 2009 Apr 8, 17:23 -0400
http://tbone.biol.sc.edu/tide/tideshow.cgi?site=New+London%2C+Connecticut&units=f New London, Connecticut 8 April 2009 - 9 April 2009 41.3550� N, 72.0867� W 2009-04-08 03:17 EDT -0.22 feet Low Tide 2009-04-08 05:27 EDT Moonset 2009-04-08 06:19 EDT Sunrise 2009-04-08 09:18 EDT 2.73 feet High Tide 2009-04-08 15:27 EDT -0.01 feet Low Tide 2009-04-08 18:42 EDT Moonrise 2009-04-08 19:21 EDT Sunset 2009-04-08 21:33 EDT 3.26 feet High Tide 2009-04-09 04:04 EDT -0.25 feet Low Tide 2009-04-09 05:52 EDT Moonset 2009-04-09 06:18 EDT Sunrise 2009-04-09 10:02 EDT 2.67 feet High Tide 2009-04-09 10:55 EDT Full Moon 2009-04-09 16:10 EDT 0.02 feet Low Tide 2009-04-09 19:22 EDT Sunset 2009-04-09 19:51 EDT Moonrise 2009-04-09 22:15 EDT 3.31 feet High Tide -----Original Message----- From: NavList@fer3.com [mailto:NavList@fer3.com] On Behalf Of Hewitt Schlereth Sent: Wednesday, April 08, 2009 5:18 PM To: NavList@fer3.com Subject: [NavList 7883] Re: Tides by bearing of the moon The method I used to use was to consider that on the day of the full moon, the luni-tidal interval listed in Bowditch for a given place would be the time of high tide. From my 1933 Bowditch, the High Water Interval for New London is 9h30m. So on the day of the full moon - tomorrow 4-9-09 - high tide at New London would be 0930 EST or 1030 DST. I don't have any tide tables here, so would a kind soul on the List look it up and see how old Nathanael did? Thanks, Hewitt On 4/8/09, frankreed@historicalatlas.comwrote: > > Hi Dave. > > Next, try some place more tropical. Hawaii perhaps? :-) That should show significantly worse behavior with respect to azimuth. > > I wrote some code a few years back to do tidal calculations. It's much shorter than the widely available X-tide code and only marginally less accurate: http://fer3.com/arc/m2.aspx?i=100454. > > Here's a question that's been in the back of my head for a long time... which is a better predictor of tide times: the local hour angle of the actual Moon or the local hour angle of the mean Moon (which we can imagine moving along the celestial equator with constant angular velocity)? > > -FER > > > > > > > "Confidentiality and Privilege Notice The information transmitted by this electronic mail (and any attachments) is being sent by or on behalf of Tactronics; it is intended for the exclusive use of the addressee named above and may constitute information that is privileged or confidential or otherwise legally exempt from disclosure. If you are not the addressee or an employee or agent responsible for delivering this message to same, you are not authorized to retain, read, copy or disseminate this electronic mail (or any attachments) or any part thereof. If you have received this electronic mail (and any attachments) in error, please call us immediately and send written confirmation that same has been deleted from your system. Thank you." --~--~---------~--~----~------------~-------~--~----~ Navigation List archive: www.fer3.com/arc To post, email NavList@fer3.com To , email NavList-@fer3.com -~----------~----~----~----~------~----~------~--~---