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Re: Transcription of Worsley's Log
From: Brad Morris
Date: 2009 Mar 23, 22:26 -0700
From: Brad Morris
Date: 2009 Mar 23, 22:26 -0700
Hi Henry After a tremendous amount of typing, I finally saw what you were saying and started over. We agree, Worsley saw his longitude as West 54-50-00 and we think, based on modern charts, that the longitude is West 54-53-45. This gives us a delta longitude of 00-03-45. So why does my 2.13 not agree with your 1.804? I used a great circle distance, accounting for the difference in latitude as well as the distance in longitude. Your calculation, I believe, accounts only for the DLO. Fundamentally, these values are fairly close and not truly worthy of extended discusion. ---------------- This is the point I am trying to drive at, however. If his observation and consequent reduction yields West 54-19-45 and he "knows" West 54-50-00, then his DLO is 00-30-15 (arc). If we convert this arc to time, we should get 2 minutes 1 second of CE, not 1 minute 4 seconds. This is where I would like a bit of help in my understanding. I think from your equations of the other day that {you think} he estimates his distance to Cape Belsham at 1 minute 4 seconds (time) and therefore he must subtract that out from his CE. That supposes that there are 16 minutes of arc to Cape Belsham from Point Wild. That is very high of the mark. He can see it from Point Wild pretty clearly. I measure it on my chart 29104 at 00-01-30 arc. So 1 minute 4 seconds time should really be much lower, or roughly 6 seconds time. Thats a 58 second delta. If you read Worsley's note on 7 May 1916, he states that he is "about" 20 miles astern due to his CE, on an easterly course. So even Worsley knows his chronometer is slower than he expected. This can be attributed to (1) Worsley doesn't have a good idea of the rate of his chronometer. (2) Worsley doesn't get the right value for CE on Elephant Island. Which one? I simply don't know. I find both outcomes strange. He should know the rate of his chronometer after working with it on this expedition. Maybe he just started working with this pocket chronometer after abandoning all others on the ice. He also knows the longitude of Cape Belsham fairly well (not to modern values, but not too far off). ------------------------------------------- Your calculation was Meridian angle 02-55-24.6 East (in time) 11-59-60 LAT 09-04-35.4 GAT 12-41-54 Longitude 03-37-18.6 W (time) = 54-19-39 W (arc) DLo Cp Belsham 00-01-04.0 W (time) = 00-16-00 W (arc) Calc Lo Cp Belsham 03-38-22.6 W (time) = 54-35-39 W (arc) True Lo Cp Belsham 03-39-32.2 W (time) = 54-53-02 W (arc) Diff = CE, Slow 00-01-09.6 (time) = 00-17-23 (arc) The "Dlo Cp Belsham" is too large. It should read 00-00-06 W(time)=00-01-30 W (arc). Another very minor point, the "True Lo Cp Belsham" should read 54-50-00, not 54-53-02 (thats the modern value). This would reduce the time downwards from 00-01-09.6. --------------------- I do appreciate your time on these points Henry. It is helping me to get this right! Best Regards Brad Morris --~--~---------~--~----~------------~-------~--~----~ Navigation List archive: www.fer3.com/arc To post, email NavList@fer3.com To , email NavList-@fer3.com -~----------~----~----~----~------~----~------~--~---