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    Z tangent formula
    From: Bill B
    Date: 2005 Feb 16, 17:52 -0500

    George
    
    
    Regarding a formula you gave for finding azimuth:
    
    "This formula is-
    
    Tan Z = sin (hour-angle) / (cos (hour-angle) sin lat - cos lat tan dec)
    
    and the rules for putting Z into the right quadrant, 0 to 360, clockwise
    fron North, are-
    
    If tan Z was negative, add 180 deg to Z. If hour-angle was less than 180
    deg, add another 180 deg to Z."
    
    By hour-angle I assume you mean local hour angle?
    
    I was also having trouble sporting out the parenthesis.  Should the formula
    look like the following, if I let ha= (hour-angle)?
    
    Tan Z =              sine ha
            _________________________________________
    
            (cos ha * sin lat) - (cos lat * tan dec)
    
    Thanks
    
    Bill
    
    
    

       
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