NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Avoiding Wx Problem
From: Robert Owens
Date: 2000 Dec 15, 6:20 AM
From: Robert Owens
Date: 2000 Dec 15, 6:20 AM
I have been studying for my Masters license and have come upon this problem: You are underway on a course of 050T at a speed of 12 knots. The eye of a hurricane bears 120T, 110 miles from your position. The hurricane is moving toward 285T at 25 knots. If you maneuver at 12 knots to avoid the hurricane, what could be the maximum CPA.(Closest Point of Approach)1 The listed answer is 77 miles. I don't have a clue how to figure this one out. My Bowditch must be hiding the obvious but I can't find it. My first inclination is to draw the hurricane vector, then at the west end of it draw a 12 mile arc, the draw a line from the east end of the hurricane vector to the arc. that gives me about a 313T. Then I don't get anyway near a 77 mile answer. More like 60 miles. Help. Bob Owens TUGLY 26' Nordic Tug
