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Re: Cylindrical Slide Rule / tube lengths
From: Gary LaPook
Date: 2010 Jan 29, 23:48 -0800
From: Gary LaPook
Date: 2010 Jan 29, 23:48 -0800
I priced out the components today. The two inch plugs are $3.90, $7.80 for two. The threaded rod is $3.59 for 36 inches which I can cut to make three pieces long to make three locking devices. A self locking nut is $0.45 and a regular nut is $0.11. So with sales tax the parts for the locking mechanism come to $10.40 plus postage. If anybody is interested let me know. gl Gary LaPook wrote: > If you want to use the locking device that I came up with and you > can't buy the components where you are I could purchase them here and > ship them to you. The plugs cost about five dollars each, you need two > of them, and I think the threaded rod was about the same. I think it > would cost about twenty dollars for all the components including > postage if anybody is interested. > > gl > Wolfgang Hasper wrote: >> I received a sample of those laminated paper tubes. >> >> The exterior surface is very smooth and even, rather matte than >> glossy. I am sure it can be used to put on printed scales without >> further treatment. >> >> By the way: I found white adhesive film in A4 size that can be used >> in a laser printer. >> >> the interior surface is glossy, due to production on a core tube. (it >> is a coiling production process. No noticeable seam or other >> irregularity from the coil end on the outside though.) >> >> For ease of transport and to save on cost there the tubes should be >> cut to length at the manufacturer's. >> They provide precise cuts to right-angles which I think is a huge >> benefit and valuable help for our futher work. I will shortly receive >> information on the cutting cost. >> >> As I find only now those lengths are not sufficiently known yet. >> RvR's paper gives account of the visible: >> >> inner tube something > 230mm with 198 mm of scale intermediate >> tube 225 mm >> outer/cursor tube 222 mm (this is reliably the true length of the >> tube) >> >> The intermediate tube will for sure extend into the base and end just >> before the "upper" cursor cut-out (marked II). (assumed cursor tube >> on zero stop) So the inner tube is visible there. >> >> The inner tube itself will be long enough to be sufficiently >> stabilised when fully drawn out, yet short enough to leave some space >> for the locking mechanism down in the base region (when slide rule is >> fully closed) >> >> Assume the black base is a "cup" slipped on the end of the >> intermediate tube. >> >> I will make a sectional drawing to determine the missing lengths and >> post it for discussion. Any comments welcome. >> Would you please tell me if anybody wants to have non-HR lengths? >> >> Wolfgang >> >> >> >> >> > > > > >