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Re: Exercise #5 Lat/Long near Noon.
From: Andrés Ruiz
Date: 2008 Jun 2, 10:25 +0200

Jeremy,

I have attached the Hs and time of LAN using Least squares fitting:
The curve equation is: Hs = a0+a1*t+a2*t2
The maximum gives: 
t LAN =     -a1/(2a2)
Hs LAN =    a0-a2t2

Andrés

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File: 105244.latlong-noon-ls.xls

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