NavList:

Dear Tony,

Thanks for submitting a new set of observations.

Please be so kind as to refer to the enclosed document.

Further to our private exchanges, I first solved your observations through computing 6 different positions representing 6 intersections of the Equal [averaged] Heights Circles.

I then averaged such 6 Latitudes and 6 Longitudes to get : Position ④  N60°08.17’ E029°56.15’

Then I processed your data as Classical LOP's through "gathering" the observations in 2 different ways :

(1) : under a 1st set of 12 averaged observations. And finally :

(2) : under a 2nd set of 9 averaged observations.

In both cases (1) and (2) I am getting final positions extremely close from one another with both Position③  and Position ⑥ showing at N60°07.9’ E029°56.1’ which is believed to be the best Position result which can be obtained from your data.

BTW, what was your GPS position then ?

Best Navigational Regards,

Antoine