NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
From: Grace O'Farrell
Date: 2016 Jul 6, 19:17 +0100
Hi Gary,
My confusion was fining z in the C tables but I found that instead of using the C tables in order to find it I can use a formula of tan Z = 1/C x cos Lat which helped then I was able to find the True Azimuth by converting. So in the end as it was in the NW I took Z away from 360 and found my answer. Some of the links you have given are going to be a lot of help so thank you very much for them.
Kind regards,
Grace.
Is your confusion about the calculation of the "azimuth angle," "Z" or is it in converting "Z" into "Zn" the true azimuth?
These old posts might be of help to you. The discussion of the Rust Diagram includes rules for that conversion.
http://fer3.com/arc/m2.aspx/Fw-Chichesters-Calculations-correction-LaPook-dec-2008-g6705
http://fer3.com/arc/m2.aspx/Fw-Chichesters-Calculations-LaPook-dec-2008-g6704
http://fer3.com/arc/img/106704.chichester-234-2.pdf
http://fer3.com/arc/m2.aspx/Fw-Chichesters-Calculations-LaPook-dec-2008-g6700
http://fer3.com/arc/img/106707.sin-cosine-1.pdf
http://fer3.com/arc/m2.aspx/Rusts-diagram-for-computing-azimuth-LaPook-oct-2007-g3383
gl
