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Nope I can't since that is the only website I have. I only set it up in 
response to the wild claims made by TIGHAR about where Earhart ended up, 
TIGHAR has made a lot of money from contributions from a gullible public out 
of those claims with the head guy paying himself $238,000 a year out of his 
"tax exempt non-profit" which rubbed me the wrong way."

gl
--------------------------------------------
On Fri, 1/15/16, Tom Sult  wrote:

 Subject: [NavList] Re: Borrowed Bygrave
 To: garylapook@pacbell.net
 Date: Friday, January 15, 2016, 7:57 AM
 
 Can
 you send your website?  Tsult---.com. When
 I google you I find lots of your stuff about  Amelia
 Erhardt but a general website I do not find. 
 
 Tom Sult, MDAuthor: JUST BE WELLjustbewell.info
 On Jan 15, 2016, at 03:57, Gary LaPook 
 wrote:
 
 If you
 read the rules for special cases in these photos of the
 Bygrave you will find that CPT Bygrave tells us how to
 compute the altitude when the declination is less than the
 lowest number on the scales. He tells us that  to find
 the altitude in this case that you interchange the
 declination and the assumed latitude since the astronomical
 triangle works from both ends, the altitudes, as calculated
 from either end (GP or AP,) must be the
 same. 
  BUT, he
 doesn't tell us how to find the azimuth!
 I had to
 invent a method for this situation and it is on my
 
website.==============================================================================================When 
declination is less than one
 degree you can't begin the computation the normal way to
 find "W" because you have to start the process
 with declination on the cotangent scale and this scale
 doesn't extend below 1º. So in this case you just skip
 the computation of "W" and simply set
 "W" equal to declination. Using this method you
 arrive at an azimuth that is not exact but is a close
 approximation and in the worst case I have found the azimuth
 is still within 0.9º of the true azimuth but most are much
 closer. If the declination is less than one degree and the
 latitude is also less than one degree, follow this procedure
 and also assume a latitude equal to one degree. After you
 have computed the Az you then follow the same procedure
 discussed above for azimuths exceeding 85º by interchanging
 the latitude and declination and then computing Hc which
 will produce an exact value of Hc.
 
 ====================================================
 gl
     
  
 From: Gary
 LaPook 
  To:
 garylapook---.net 
  Sent:
 Thursday, January 14, 2016 6:47 PM
  Subject:
 [NavList] Re: Borrowed Bygrave
    
 i took
 these photos at the Science Museum in London.gl
 
 
 
 
 
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