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Re: Calculated slope question
From: Gary LaPook
Date: 2010 Dec 15, 00:25 -0800
From: Gary LaPook
Date: 2010 Dec 15, 00:25 -0800
See attached file: On 14/12/2010 23:38, Gary LaPook wrote: > Jeremy, > > Here is a table for Motion Of the Observer correction for 18 knots and > 5 minutes. > > The first row is the relative azimuth for bodies ahead of the beam and > the sign is plus (+) > > The second row is the size of the correction in minutes of arc. At 18 > knots the maximum correction, which is for bodies straight ahead or > straight behind, for a 5 minute period is 1.5'. The correction is > always zero for bodies exactly on the beam. > > The third row is the relative azimuth for bodies abaft the beam and > the sign is minus (-). > > > + 0 15 26 34 40 > 46 51 55 60 > 64 68 73 77 80 > 84 88 > > > 1.5 1,4 1.3 1.2 > 1.1 1.0 .9 .8 .7 > .6 .5 .4 .3 .2 > .1 0 > > > - 180 165 154 146 140 > 134 129 125 120 116 > 112 107 103 100 96 92 > > > > > gl > >