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A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Calculator question
From: Alexandre Eremenko
Date: 2005 Feb 21, 11:16 -0500
From: Alexandre Eremenko
Date: 2005 Feb 21, 11:16 -0500
I agree with this: On Mon, 21 Feb 2005 WSMurdoch@aol.com wrote: > 3 MB is far more memory than is really necessary for a celestial navigation > calculator unless you write software like one of Bill Gates's employees. I like "minimalist" solutions. What I really need is 3 NUMBERS stored in the memory, not 3MB:-) I don't mind using paper Almanach. And for solving nav triangle with the usual sin h formula, one needs 3 numbers stored in the process. When doing this with Casio, I have to re-enter the same data twice. This takes few seconds of course, but entering the data is a major source of errors. Question to Bill: > Here are the memory requirements used in a TI-82 program that I wrote in the > early 1990's using TI basic. > To input time and convert to a single unit - 468 bytes > To calculate a few time dependent constants - 227 bytes > To input a position - 400 bytes > To calculate almanac data to +/- 0.01 (2 S.D.) accuracy - > Sun - 650 bytes > Moon - 1448 bytes What do you exactly mean by "calculating almanac data"? Can you explain how you calculate Moon's coordinates using 1448 bites?? The formula for the Moon that I am find in Meus contains hundreds of terms! Alex.