NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Celestial Course
From: Adrian P. Vrouwenvelder
Date: 1998 Mar 18, 6:18 AM
From: Adrian P. Vrouwenvelder
Date: 1998 Mar 18, 6:18 AM
Ref: Note from Ruth Summers (attached)
[snip]
> So, I'd really like to see something we all could work together on.
> I am currently working with another lady to figure out this celestial stuff.
> We have books, tables, more books, I just ordered some videos.
> For crying out loud, what makes this so damned hard !!
> -ha probably the *&^%$ math.
The math is easy. As Dan Hogan mentioned, it's add, subtract, multiply
and divide (mostly just add and subtract if you use ho229 and all the
neat tables).
>
> Although I can see after my minor investigation into this that I think the
> angles of measurement is where the math is needed, ie-usually the boat is tilted
> but the GP is that line coming out of the earth and it's straight.
Boat heel has no bearing on your navigation. Forget about it.
>
I've noticed that some books show _how_ to do celestial, but
don't really do a good job of painting the "big picture" so you can
keep everything in perspective. Here's my attempt at a big picture.
1. Given that you know your distance from three known positions on the
planet, you can draw three circles of position. The point at which
all three circles intersect is your position. (Two overlapped
circles define two points of intersection; the third circle should
intersect at or near one of those two points).
2. If a star is directly overhead (i.e. exactly 90deg to the horizon),
you are at its geographic position (GP) and your distance from it
is zero (0). If you can see a star at your horizon (corrected
for dip, refraction and all) so that it measures 0deg to the
horizon, you are 1/4 of the planet's circumference from its GP.
Got that? That amounts to 5400 nautical miles (because the
there are 60 nautical miles at earths surface for every degree
of arc).
If the star measures 45deg, you're 2700 miles from its GP.
And so on. The point is, the angle you measure off the horizon
to the star is directly convertible to your distance from its
GP. If you knew its GP, you could plot your circle of position.
3. Sextants measure angles. Period. However, the angle you measure
with the sextant (Hs) must be corrected for dip, refraction of the
atmosphere, index error, and some other factors. This is easy to
do using the nautical almanac, which contains some easy-to-use
tables facilitating this correction. The result is Ho, for
"Height observed."
4. The Geographic Positions of celestial bodies are obtained from the
Nautical Almanac, and will ultimately be expressed in terms of
GHA (Greenwich Hour Angle) which expresses the star's position
with respect to Greenwich, and Declination, which corresponds
to the GP's "latitude."
If you had a very large chart and could draw very large
circles, you could stop here. You would not need sight
reduction. However, you probably have a small chart spanning,
say, 80x80 nautical miles, so charting the GPs of all of your
celestial bodies is impractical. Therefore, you need sight
reduction.
5. Sight reduction allows you to plot your celestial circle fragments
of position on a small chart (using straight lines as
approximations of those circle fragments). Basically, since
you don't know where you are, but have a pretty good idea (i.e.
"somewhere on this chart"), you pick an arbitrary spot on the
chart. The sight reduction procedure then ultimately tells
you how to draw your line of position (the line on which your
vessel is) relative to the point you chose. The procedure does
this by giving you "Height computed" (Hc) an azimuth (Z, given
as a true bearing), and a direction (away from or towards the
celestial body along the azimuth).
You take the difference of Hc and Ho to come up
with a distance (remember there are 60 miles in a degree).
When you've digested all of this, we can talk about how to
plot your LOP using the Hc, Z, and direction.
I used the word "star" a lot, but any celestial body (planets, the sun
and the moon) will do. The principle remains the same, though the
correction and reduction procedures do vary a bit.
Adrian P. Vrouwenvelder
Durham, NC.
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