NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Easy Lunars in 1790
From: Alexandre Eremenko
Date: 2006 Apr 28, 19:45 -0400
From: Alexandre Eremenko
Date: 2006 Apr 28, 19:45 -0400
Walter, It has to be double checked yet, but I suspect that in my favorite Volkovyski example (cited in our paper in Iberoamericana), all singularities are true (have branches which do not return when you continue on a Jordan curve), and there are uncountably many of them. So they are not K. Thus it seems that no good conjectures remain. 1. True (in the sense above) cannot be on the boundary of the completely invariant domain. 2. Direct implies true. (So you fixed the bug in our paper with Liubich). 3. True does not imply direct. (Simple example). 3. True implies linearly accessible. 4. But not vice versa, by your wonderful example. 5. True can be uncountably many (and thus true does not imply K). 6. K does not imply true (Take a K-singularity described in Goldberg's paper. Topologically it is like (sin z)/z). What else to ask? Alex