NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Equation for dip?
From: James R. Van Zandt
Date: 2006 Sep 30, 23:01 -0400
From: James R. Van Zandt
Date: 2006 Sep 30, 23:01 -0400
Geoffrey Kolbewrote: > I grabbed an old Nautical Almanac, opened it randomly and lo and behold, > > d = 0.0293*h^0.5 where d is in degrees and h is height of eye above > the horizon (sea level) in metres. If you work out the geometry, you find d = sqrt(2*h/Re) where Re is the radius of the earth. In radar analyses, it's usual to use the "four-thirds earth model", i.e. d = sqrt(2*h/(1.33*Re)) which corrects for refraction. See for example: http://twister.ou.edu/papers/Gao_Xue_Brewster_AAS2006.pdf The NA formula above works out to d = sqrt(2*h/(1.2*Re)) which is a "six-fifths earth model", i.e. less refraction. I wonder whether that's because of the different wavelength, or different typical heights (so different temperature and pressure profiles), or what? - Jim Van Zandt --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to NavList@fer3.com To , send email to NavList-@fer3.com -~----------~----~----~----~------~----~------~--~---