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Re: Exercise #13 Azimuth of a planet
From: Jeremy C
Date: 2008 Jun 14, 01:20 -0700
From: Jeremy C
Date: 2008 Jun 14, 01:20 -0700
SOLUTION On Jun 13, 6:34�pm, Anabasiswrote: > Exercise #13 �Azimuth of a planet > > On 13 June 2008, a ship is approaching anchorage. �On the gear test > check off list, there is a box stating �gyro error calculated and > posted.� �The sky is mostly overcast and the sun looks like it will be > obscured by clouds for most of the morning. �Fortunately abaft of the > starboard beam, Jupiter is shining brightly in the late morning > twilight. �The alidade was set up on the starboard gyro compass > repeater and a bearing was taken at 05h 29m 00s ZT. �(ZD -10). �The > bearing was 232.7 degrees. �The ship is in position Latitude 15deg 14� > North, Longitude 145deg 07�East. �Determine the gyro error for > arrival. > > Jeremy UTC: 19h 29m 00s 12 June 2008 GHA hr 254deg 10.4� Tcorr 7deg 15.0� Vcor (2.7) 1.3� GHA 261deg 26.7� +Long 145deg 07.0 LHA 046deg 33.7� Lat 15deg 14�N Dec S 21deg 59.3� Z = 51.8 (by calculator) Zn = 231.9 GE= 0.8 deg West I will note that this is exactly what I did to check off my list during my gear test coming in the other day. Jeremy --~--~---------~--~----~------------~-------~--~----~ Navigation List archive: www.fer3.com/arc To post, email NavList@fer3.com To , email NavList-@fer3.com -~----------~----~----~----~------~----~------~--~---