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    Re: Height of Eye (He) Value for Beach Shots?
    From: Frank Reed CT
    Date: 2006 Jul 6, 15:54 -0500

    "Yabbut.... seems like a bit of circular logic to me - won't I need a
    height of eye value here first in order to determine the angle to the
    true horizon? "
    
    Your floating target might be something like 30 or 40 degrees down from
    the horizon. Dip is only going to be a few minutes of arc, ten at the
    outside, so it's negligible for this little calculation. Of course, if
    you want to be extra careful, you simply run the calculation twice. On
    the second pass, you add the first estimate of dip to the measured
    angle. In practice, it won't make much difference.
    
    "wouldn't it be easier to just dangle a tape measure
    down to the water's edge?  :-)"
    
    Maybe! But I've actually done this, and it works. Using a styrofoam
    sighting target probably made it sound more complicated than necessary.
    Find yourself a bit of driftwood. Measure its size in feet as well as
    you can. Then toss it out into the water (no one will find this
    suspicious). Two quick angles and a very short calculation will give
    your height of eye:
    ht = L*sin(B)/sin(A)
    where L is the length of the target, A is the angular size of the
    target, and B is the angle between the horizon and the target. Note
    that if the target is a "stick", much longer in one dimension, you have
    to wait to measure its angular size until it has rotated around and is
    perpendicular to your line of sight.
    
    Suppose the water is a bit too far for tossing sticks. In that case,
    can you estimate the distance from where you're standing to the water's
    edge by some other means? If so, you can get height of eye by a reverse
    "dip short" calculation.
    
    -FER
    
    
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