NavList:

This is how Father Larry Duff would have explained the big cow small cow bit if he hadn’t driven off the cliff.

Forget the Moon for the moment; leave that to the Apollo crews.  This is how a fighter pilot might see it.

1.  Find the apparent length of the F22 by comparing the F22 and the TU-95 on the photograph.  On my copy of the photograph (to save scratching my 22” monitor screen) I measured the TU-95 as114mm long and the F22 as 71mm long.  Therefore, if the TU-95 is 46.2m long, the apparent length of the F22 is 71x46.2/114=28.8M long.

2.  In my diagram, I’ve drawn a line down from the TU-95 calibrated in metres (and also in Tu-95 wingspans as the TU-95 wingspan is near enough 50M)

3.  I’ve also drawn a line down parallel to the line described in (2) and a distance from it equal to the F22’s true length.

4.  I’ve also drawn an unsafe sector were the Tu-95 and the F22 would be inside wingtip to wingtip distance.

5. Next, I placed my ruler from camera positions 50, 100, 150, 200, and 250M from the Tu-95 to the apparent length of the F22 against the side of the TU-95 and marked where the ruler crossed the F22 true length line.

Results:
If the F22 pilot was wingtip to wingtip with the Tu-95, which is where fighter pilots like to be, the F22 centreline would be 32M from the Tu-95.  This would put the camera at 86M from the Tu-95.  
A slightly more comfortable 36M apart would put the camera 100M (two Tu-95 wingspans away). 
A sensible 52M between centrelines would put the camera 150M away, and a weenie 70M between centrelines would put the camera 200M away.

Returning to the Moon:
I did play around trying to measure the Moons altitude by measuring the number of Moon diameters to the horizon in the photograph, but the horizon is so poorly defined, as is the aircraft height to calculate dip and refraction that Hc Moon could be anywhere between 5 and 8 degrees, so it’s not much help in defining the exact sunrise/sunset day.
That's my brain exercise done for this week.  DaveP

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