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A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
ICE (Interactive Computer Ephemeris) accuracy
From: Paul Hirose
Date: 2014 Mar 31, 21:12 -0700
From: Paul Hirose
Date: 2014 Mar 31, 21:12 -0700
I wrote: > Regarding ICE, the delta T of this old program has become excessive, > with some impact on Moon coordinates. The effect is small. For instance, at 2014 March 29 12:00 UT1, latitude, longitude, and height all zero, the ICE celestial navigation data for the Moon agree exactly with the USNO online calculator, except that GHA is .1′ too small. Compare ICE unrefracted altitude to JPL HORIZONS: 74 01 42 ICE (includes parallax in alt.) 74 01 38 JPL HORIZONS Greenwich apparent sidereal time: 00 27 15.5401 ICE 00 27 15.5341 JPL HORIZONS ICE assumes time is UT1 when it computes navigation data and sidereal time, but HORIZONS assumes UTC. On this date UT1 is .20 second behind UTC, so 12:00:00.00 UT1 = 12:00:00.20 UTC. The latter time must be input to HORIZONS to get comparable values. That's what I did. However, for geocentric position computations ICE assumes the time you input is TT. HORIZONS will take time in that scale, so no adjustment is necessary for geocentric apparent Moon RA and dec. at 12 h TT: 23 24 26.401 -00 24 42.98 ICE 23 24 26.39 -00 24 43.1 HORIZONS The separation between those positions is .2″. HORIZONS has an option to generate output with more precision, but I didn't think that necessary. Hc in the navigation data is the only value with significant error, and that's only about a tenth of a minute. (I converted outputs from both programs to DMS format for easier comparison.) Since ICE's sidereal time and geocentric apparent place are practically perfect, the error must come from the conversion from UT1 to TT. And in fact its delta T is 78.1 s, about 11 s too great. Therefore instead of 12 h, if we use 11:59:49 UT1, the correct Moon position will be extracted from the ephemeris (which is based on TT). However, in terms of Earth rotation, that adjusted time will put the observer west of the correct position. The solution is to adjust the observer's longitude east to compensate for the time adjustment: 11 s * 15 = 165″ = .046°. Formally, we should also multiply by 1.002, the sidereal to solar time ratio. But we omit that step due to the program's relatively low input and output precision, and get: 74 01 36 ICE Hc (includes PA) 74 01 38 JPL HORIZONS As I said earlier, correcting for the delta T error makes the old program as good as new! The same method is applicable to the USNO MICA program. I wouldn't do that extra work for Sun navigational data from ICE, though. Its RA and dec. change so slowly (about 1°/day vs. 12° for the Moon) that an 11 s error in TT probably wouldn't make any significant difference. --