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Re: Ix Diagram and Pub 208
From: Gary LaPook
Date: 2012 Dec 11, 21:35 -0800
From: Gary LaPook
Date: 2012 Dec 11, 21:35 -0800
"While
trying some different examples, I discovered an interesting set of
values to use. Let dec = 30, LHA = 40, Hc = 50 and then the Z comes out
to exactly 60. There must be some trig reason for this but I haven't
figured out why. " --------------------------------------------------------------------------------- The answer just came to me in a flash. The diagram solves this equation: sin Z cos Hc = sin LHA cos dec = C ( I wrote it wrong in my first post) In my example: sin 60 cos 50 = sin 40 cos 30 = C since cos 50 = sin 40 and also sin 60 = cos 30 so Z ends up coming out exactly as 60 because it is arc sin (cos 30) gl --- On Tue, 12/11/12, hanno ix <hannoix@att.net> wrote:
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