NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Longhand Sight Reduction
From: Gary LaPook
Date: 2014 Jun 13, 08:56 -0700
From: Gary LaPook
Date: 2014 Jun 13, 08:56 -0700
(I sent this last night but it never showed up.) ----------------------------------------------------------------------- I posted this stuff before. One thing you can use a calculator for is computing the GHA of Aries. All you need to write down, or, memorize, is three numbers. First, the rate that Aries advances each day which is 59.139 minutes each day. Second, the rate of advance each hour which is 15.041 degrees per hour. The third number you need is the GHA of Aries at 0000Z on the 31st of December from the prior year which is, for right now, 99° 33.4'. Knowing these three numbers makes it easy to calculate the GHA of Aries for any time during the year. The first step is to determine how many days have passed since December 31st and this is easy since it is merely the number of the day in the present year. January 1st is one day later, etc. Just add up all the days in the months preceding the current month and then add the date of the current month. "Thirty days hath September, April......" If you haven't noticed it before, there is a pattern to the calendar, long months alternate with short months with the one exception that two long months are adjacent, July and August. So just add up all the days and multiply by 59.139 minutes per day. If you add this to the starting GHA on December 31st you would have the GHA for 0000Z on the current day but it is easier if we wait until the end of the computation to add in the starting value. The next step is to multiply the time since 0000Z today. If you are using a calculator with Degree, Minute and Second input simply put in Hours, Minutes and Seconds, convert to decimal format and multiply by 15.041 degrees per hour. Add this to the result of the first step and to the December 31st GHA and you have the value for the current time. You can also do this computation by hand but it is tedious and you have to be very careful doing the long hand multiplication but it does work without electrons. The first step is the same as above, calculate the change for the days as in the first step in the first example. So the next step is to calculate the change for each whole hour at the rate of 15.041° per hour which is the same as 15° 02.46' per hour. This is also the same as 902.46 minutes per hour, so multiply the whole number of hours by 902.46' per hour and write the result under the result from the first step. (902.46 is 15 times 60 plus 2.46.) It's easy to remember, 90 plus 2-4-6. It is quite a bit easier, if doing the computation by hand, to convert the minutes and seconds of time to decimal hours, add them to the whole hours and then multiply by 902.46. You do this conversion in two steps, divide the seconds by 60 to get decimal minutes which you add to the whole minutes. Then divide the minutes and decimals by 60 again to get decimal hours which are added to the whole hours and the result multiplied by 902.46'. It takes about 7 minutes doing the long hand multiplication. It's a lot faster with a calculator. If you also memorize the coordinates of about ten well chosen stars then you can do celnav without an almanac, completely from memory. I wanted stars well arrayed in SHA, bright, and mostly at low declinations so they could be used from both hemispheres. I settled on Fomalhaut; Altair; Vega; Antares; Spica; Regulus; Pollux; Sirius; Capella; Schedar. All are first magnitude except Schedar which is 2nd magnitude but was the best I could find to fill in the gap in SHAs. The furthest south is Fomalhaut at 29 south so it is visible in most of the northern hemisphere. Only Capella and Schedar are difficult to see from far southern latitudes. I checked my selection of stars by use of the 2102-D and in the northern hemisphere there are never fewer than three of these stars above the horizon and usually 5 to 7. In the southern hemisphere, south of 55 south, there are occasions when only 2 stars are above the horizon, but usually more, even that far south. North of 55 south there are at least 3 stars up and usually more, You can figure the dip correction in your head as simply the square root of the height of eye in feet, and the refraction correction is also easy to remember, 5 above 10° ; 4' above 12° ; 3' above 16° ; 2' above 21° ; 1' above 33° and 0' above 63°. Now just add a Bygrave, a sextant and a watch and you can navigate without any electrons or books. gl -------------------------------------------- On Thu, 6/12/14, Peter Montawrote: Subject: [NavList] Re: Longhand Sight Reduction To: garylapook@pacbell.net Date: Thursday, June 12, 2014, 2:16 PM Hi Hanno, The multiplications show each partial product separately in the array. It's less compact than the usual method, but somehow I find it more reliable to add up everything at the end. It's essentially the lattice method: ... So no-table sight reduction seems tractable. The other part of this is the almanac, and here we really have to memorize a few numbers. The minimal set might be something like (ra,dec){at}J2000 of half a dozen bright stars plus the expression for sidereal time at Greenwich (including an estimate of the current delta-T). The Sun seems a bit too complicated to memorize to any usable accuracy, let alone the Moon and planets; but any of these bodies could be used as "transfer standards" by measuring them against the stars. Here are my assumptions, which are of course pretty absurd: - available: sextant; chronometer showing UTC; pencil and paper - not available: tables or any other computational aid; almanac - known: micro-almanac of a few stars; sight reduction algorithm Hanno, just read your reply: yes, exactly, Napier's bones. The desert-island guy might well want to make a set. Cheers, Peter