NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Moonrise over Connecticut, 19 October 2021
From: Herman Dekker
Date: 2021 Oct 24, 03:20 -0700
From: Herman Dekker
Date: 2021 Oct 24, 03:20 -0700
Frank gave the info HE= 17ft. From we can calc the dip. Dip=0.97'·√HE(ft)=4'
But is there one formula for calculating how far the distance is from the observer to the visible horizon?
The normal formula for a rectangular triangle Distance= HE / tg(angle) wil give a approximation
but I suppose there is one better formula, that include the curvature of the earth?
regards
HermanD
