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Re: My first Lunar
From: Kent Nordstr�m
Date: 2008 Aug 4, 17:41 +0200
From: Kent Nordstr�m
Date: 2008 Aug 4, 17:41 +0200
Frank wrote [5988]: You found deviations as large as 0.6 minutes or arc in
the clearing with a
standard deviation of 0.3 minutes. That's a lot! Though I certainly can't
guarantee it, I believe that my clearing results are accurate to 0.05
minutes of arc so I would say that you still have some things to fix. Even
in the year 1790, a discrepancy of 0.6 minutes of arc in clearing a lunar
would have been counted as "too large" except as a rough approximation.
The results from my test cases with my input data into Frank's prediction
model [5932] were as in columns 2-3 below. All data 1-8 are in minutes of
arc directly read out from Frank's model.
I still claim that my own LD prediction model is rather precise well aware
of that I use old-fashioned methods. My results with the same input data,
except for Jeremy's first lunar - case 8, as per above in my own model give
errors in LD as per column 4. Column 5 is just a conversion to compare
figures in arc min with what I got from Frank's model. So the relevant
comparison is between column 2 and 5 :
Case
Frank's error in LD
Frank's error in longitude
My error in LD
In arc sec
My error in LD in arc min
1
0'
1'
-5,5"
-0,092'
2
0,6'
19'
-2,1"
-0,035'
3
-0,3'
10,3'
5,5"
0,092'
4
0,3'
9,6'
-1,5"
-0,025'
5
0,1'
3,3'
0,06"
0,001'
6
-0,2'
5,5'
-2,3"
-0,038'
7
0,4'
11,1'
-0,5"
-0,008'
8
0,1'
1,8'
-
-
Mean
0,125'
7,7'
-0,91"
-0,015'
Std. Dev.
0,3'
6,0'
3,3"
0,055'
Frank's comment that an error of 0,6' was to large in 1790 can be
questioned. I would say that navigators then were likely not unhappy to find
longitude within 15-20 M (0,5-0,7 min of arc in LD). The errors in my LD's
are referred to test cases taken from text books. You can of course always
ask what is correct.
Kent N
----- Original Message -----
From:
To:
Sent: Sunday, August 03, 2008 3:02 AM
Subject: [NavList 5988] Re: My first Lunar
>
> Kent, you wrote:
> "I have now made a comparison between Frank's model and mine and here are
> the results. In all cases I have used my own way to compensate for
> oblateness/flattening. By using my data in Frank's modell error in lunar
> and
> and error in longitude are read out.
> [...]
> So it seems to me that my model is rather good. The deviations are
> probably
> that I model e.g. refraction and oblateness/flatness in a different way
> from
> Frank."
>
> You found deviations as large as 0.6 minutes or arc in the clearing with a
> standard deviation of 0.3 minutes. That's a lot! Though I certainly can't
> guarantee it, I believe that my clearing results are accurate to 0.05
> minutes of arc so I would say that you still have some things to fix. Even
> in the year 1790, a discrepancy of 0.6 minutes of arc in clearing a lunar
> would have been counted as "too large" except as a rough approximation.
>
> -FER
>
> >
>
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