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    Re: Please help me with the math Re: learning sight reduction
    From: Guy Schwartz
    Date: 2006 May 4, 22:52 -0500

    Would you please be able to give me a sample problem and work through the
    answer so that I can repeat the steps and know I'm getting to the correct
    answer. I appreciate your help.
    Guy

    ----- Original Message -----
    From: "Bill Burchell" <wrburchell@earthlink.net>
    To: <NavList@fer3.com>
    Sent: Wednesday, May 03, 2006 10:14 PM
    Subject: [NavList 113] Re: Please help me with the math Re: learning sight
    reduction


    >
    > Guy wrote:
    >
    >> OK so here is the formula I have sin
    >> (Hc)=sin(dec)sin(lat)+cos(dec)cos(lat)cos(dlo)
    >> question 1 is dlo the same as LHA? if not what is dlo?
    >
    > Not certain.  I think of dlo as the smallest angle (absolute value) that
    > expresses the difference between two longitudes.
    >
    > LHA is the angle measured WESTWARD from the observer's position to the
    > body
    > (GHA).  If the body is west of the observed, that will be the same as dlo.
    > If the body is east of the observer, you will have to go all the way
    > around
    > to get to the observer.
    >
    > Example:
    >
    > AP lon 80d W
    > Body GHA (lon) 60d W
    > dlo = 60 - 80 = |-20| = 20
    > LHA = 60 - 80 = -20 = 340
    >
    >> question 2 is this formula telling me to mutiply sin(dec) by sin(lat) and
    >> then add it to multiplication of cos(dec) by cos(lat) by cos(dlo)
    >
    > Yes.  sin Hc = (sin dec * sin lat) + (cos dec* cos lat * by cos LHA)
    >
    > Order of operations:  Please excuse my dear aunt Sally.  PEMDAS
    >
    > P parenthesis
    > E exponents
    > M multiplication
    > D division
    > A addition
    > S subtraction
    >
    > Do anything within the () first, as ordered above.
    >
    > No.  You need LHA, not dlo
    >
    > NOTE:  If you are careful to always subtract AP from GHA, most calculators
    > will not mind if you feed it -20 instead of +340 as LHA.
    >
    >> question 3 if my methodlogy of question 2 is correct, then how do I get
    >> the
    >> result back to degrees and minutes for the answer Hc?
    >
    > Sine of the equation to the right of = is your answer in decimal degrees.
    > Read the manual, do what it says to convert decimal degrees to ddd/mm/ss.
    >
    >> question 4 what is the difference in accuracy of HO 240 Vs Ho229 Vs
    >> calculator?
    >
    > Your almanac explanation section will give you the range and probability
    > of
    > error for daily data.  Using almanac tables for dip, refraction,
    > time-to-arc
    > etc., could shift you an additional 0.1', maybe 0.2' worst case.
    >
    > 229 table errors for figuring d, v, d (adjustment to tabular Hc) and Z
    > might
    > be another 0.1' to 0.2" (rarely) over calculator. Most of the time these
    > rounding errors will pretty well cancel out or be smaller than sextant
    > accuracy (+/- 0.15 to 0.3') and operator/refraction/dip errors on the
    > water.
    >
    > NOTE:  The calculator carries a lot of digits past the decimal point, that
    > in theory are not significant digits anyway given the input.
    >
    > NOTE:  If you really want to be picky, find a v factor for the sun by
    > taking
    > the GHA difference for 24 or 48 hours and dividing by 24 or 48 and adding
    > or
    > subtracting from 15 (sun) to get a real angular speed.  Won't matter much
    > at
    > the 10-minutes-past the-hour mark, but can shift you 0.1' at the 40-50
    > minute mark.
    >
    > I think 249 tables (solving the spherical triangle etc.) are less accurate
    > than 229, but cannot speak to that from experience.  249 table books are
    > smaller, but have limits on the stars you can use.
    >
    > Of any help?
    >
    > Bill
    >
    >
    > >
    >
    >
    > --
    > No virus found in this incoming message.
    > Checked by AVG Free Edition.
    > Version: 7.1.392 / Virus Database: 268.5.2/329 - Release Date: 5/2/2006
    >
    >


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