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A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Position from crossing two circles : was [NAV-L] Reality check
From: Michael Dorl
Date: 2006 Jun 7, 06:39 -0500
From: Michael Dorl
Date: 2006 Jun 7, 06:39 -0500
At 06:10 AM 6/7/2006, George Huxtable wrote: >I have written a program in bastard-Basic which runs on my 1980s Casio >programmable calculator (FX 730P or FX 795P), and if anyone is >interested would be happy to send it or post it up. It would be simple >to adapt it to another machine. It takes the 6 quantities, dec, GHA, >and altitude for each of two bodies, and returns two possible >positions in terms of lat and long, for the user to choose the >appropriate one. It does not require a DR or AP, and provides an exact >result without going through an iteration process. > >It's not original, in that versions of the method have been described >previously beforehand. For example, in an article by George Bennett in >the journal "Navigation" (which is, I think, the American one) Issue >no. 4, vol 26, winter 1979/80, titled " General conventions and >solutions- their use in celestial navigation", and to the book >"Practical navigation with your calculator", by Gerry Keys, (Stanford >maritime, 1984), section 11.12. The method has also been described in >"The K-Z position solution for the double sight", in European Journal >of Navigation, vol.1 no, 3, December 2003, pages 43-49, but that >article was bedevilled by printing errors that render it more-or-less >unintelligible, which were corrected in a later issue. Not to mention >several serious errors and misunderstandings by the author, which have >never been acknowldged or corrected in that journal. George: Do any of these sources spell out the math in detail? I've searched in vain for a complete algorithm so a long time ago, I sat down and worked out the math. One of the tricky things is determining what quadrant angles lie in when doing a inverse trig function. I have a c++ windows application which will find all the equal altitude circle intersections for a set of observations. It also can plot the equal altitude circles on a world map. Mike