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    Re: Practical limits to distance off by VSA
    From: David Pike
    Date: 2023 Mar 29, 13:48 -0700

    Frank you wrote: Forgive me if I don't repeat it all. 

    Yes, I thought of using circular arc measurements.  I could then have had two right angles, one at each end of the arc, except a. I was too lazy to remember my geometry of a circle (last seriously revised June 1959 for UK Maths 'O' levels.   So, circumference=2pi x radius, so height = 2pi x distance x  theta minutes/360 x 60.  Therfore distance= height x 360 x 60/2 x 3.14159 x angle in minutes = 3438/angle in minutes.) , and b. I had Norie's Tables open in front of me and I didn't want Imray, Laurie, Norie or Wilson turning in their graves, especially since they had tan theta = h/d spread across the bottom of each of the relevant pages.  DaveP 

       
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