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    Re: Set and Drift
    From: Eddie C. Dost
    Date: 2006 Jun 7, 03:50 +0200

    Hi Bill,
    
    I get (almost) the same result as the solution requested:
    
    True course is 45d.
    COG is 51.9d.
    Distance travelled is 7.9nm.
    
    So far so good.
    
    I am used to extending the distance to speed, so I get
    7.9nm * 60min/h / 52min = 9.1kts SOG
    
    Using Vector math and solving (polar (r, phi) vectors):
    
    (9.1kts @ 52d) - (9.2kts @ 45d) = (1.12kts @ 143.6d)
    
    Varying the SOG/COG values just a little yields very different
    results. Taking such values of a plotting paper or a chart is
    mostly "guess work". I use a rough estimate to call an answer
    to such a question as in your example correct when drift is within
    +/- 0.2 nm and set is withing +/- 10 degrees when I have to correct
    such exams.
    
    Something seems to be off with your triangle calculations, as
    your results up to that point are the same as I have.
    
    Hope this helps,
    Eddie
    
    On Tue, Jun 06, 2006 at 08:56:40PM -0400, Bill wrote:
    > > I'll forward your "problem" to where I work, where I can look at the chart and
    > > see where they came up with their answer.  Sorry I can't help sooner.  I'll
    > > try to have an answer to you around 00h00 (UTC) 8 Jun.
    >
    > Thanks Pete
    >
    > I initially worked it without a chart using rectangular to polar conversion:
    >
    > dLat 4.9
    > dlon 8.3
    > Mean Lat 41d 13' 27"
    > Conversion factor, lon to nm
    > = mean lat cosine = .752137015
    > .752137015 * 8.3' lon = 6.242737222 nm
    >
    > After R to P conversion:
    > Distance = 7.936105344 nm
    > True = 051d 52' 16.3"
    >
    > C (psc)  056
    > D        +04 E
    > M        060
    > V        -15W
    > T        045
    >
    > One angle of the oblique triangle
    > = 051d 52' 16.3" - 045d = 006d 52' 16.3"
    >
    > One adjacent leg = 7.936105344 nm
    > The other = time * speed = 52 min * 9.2 = 7.9733333 nm
    >
    > Using the law of cosines the drift leg = .954121933 nm
    > Using the law of sines to derive the other angles and doing a bit of
    > geometry, I come up with set of 136d 00.4'
    >
    > Plotting it graphically on the chart, on a plotting sheet, and in a computer
    > drawing program, my results agree within +/- .05 nm and +/- 1d, so I am at a
    > loss.
    >
    > Bill
    
    --
    __________________________________________________brainaid______________
    Christian Dost          brainaid GbR              Bluecher & Dost
    software                Monheimsallee 45          phone +49 241 5151 138
                            D-52062 Aachen            fax   +49 241 5151 139
    ecd@brainaid.de         Germany                   cell  +49 172 9312808
    
    
    

       
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