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Re: Silicon Sea: Leg 82 results
From: Paul Hirose
Date: 2001 Dec 16, 12:08 AM
From: Paul Hirose
Date: 2001 Dec 16, 12:08 AM
Silicon Sea Leg 82 answers. Solution by 10-inch slide rule and
mid-latitude sailing. For the Sun lines I used the U.S. Naval
Observatory Web page, not having a current almanac. However, I
interpolated the coordinates between exact hours to simulate the
almanac as closely as possible.
Compute course to landfall at Hawaii:
19 30 N destination lat.
11 30 N fix 2001 July 11 0340
-----
8 00 DLat (lat. diff.) = 480 min
154 45 W dest. lon.
132 30 W fix 2001 Jul 11 0340
------
22 15 DLo = 1335 min
15.5 Lm (mid lat) = mean of dest. & fix lats
1289 p (departure) = DLo cos Lm
290 C (course) = 360 - arctan(p / DLat)
-11 correction for variation & deviation
----
279 CC (compass course)
1368 nm Distance = p / (sin C)
==========
1. Compass course from last fix to Hawaiian landfall = 279.
2. Current is practically on our stern, so speed made good = speed
thru water + drift = 10.4 kt.
==========
1170 D (distance)
11 30 N Fix lat 2001 Jul 11 03:40 Z
6 40 DLat = 400 min = D cos C
-----
18 10 N DR lat 2001 Jul 15 20:11 Z
14.8 Lm = fix lat + 1/2 DLat
1100 p = 1170 sin C
17 40 W DLo = 1138' = p / cos Lm
132 30 fix lon 2001 Jul 11 03:40 Z
------
151 28 W DR lon 2001 Jul 15 20:11 Z
==========
3. DR at 2001 Ju1 15 2011 Z = 18 10 N 151 28 W
==========
Reduce sun line at this position.
61 20.6 Hs Sun LL Jul 15 20:10:35 Z
-2.9 dip
-2.5 IC
15.4 R + SD
-------
61 30.6 Ho
118 30.3 N21 24.9 20h Sun GHA & dec
133 30.2 N21 24.5 21h
-------- -------
14 59.9
-.1 -.4 Sun v & d
118 30.3 GHA 20 h
2 38.8 increment 10 m 35 s
0.0 v corr.
--------
121 09.1 GHA at sight time
360 00.0
-151 28.0 assumed lon.
---------
329 41.1 LHA at sight time
30 18.9 t
N21 24.9 dec 20 h
-.1 d corr.
--------
N21 24.8 dec at sight time
Use Bayless version of HO 211 for sight reduction.
t 30 19 A 29690
dec N21 25 +B 3107 A 43753
A 32797 -B 5420 B 5420 A 32797
K N24 26 A 38333
L N18 10
K-L 6 16 +B 260
Hc 61 20 A 5680 -B 31902
Ho 61 31
int 11 toward Z N 78 E A 895
Correct the DR by "sailing" 11 miles toward the body.
11 D (distance)
78 C (course)
18 10 N DR lat
0 02 DLat = 2 min = D cos C
-----
18 12 N EP lat 2001 Jul 15 20:11 Z
-----
14.2 Lm (mid lat)
11 p = D sin C
151 28 W DR lon
- 0 11 DLo = 11' = p / cos Lm
------
151 17 W EP lon 2001 Jul 15 20:11 Z
Update EP to the 2001 Jul 16 0144 Z sun sight.
16 01:44
15 20:11
--------
5:33 elapsed time since last EP
57 D (distance) = 10.2 kt * 5 h 33 m
290 C (course) (use 70 for trig functions)
18 12 N EP lat 2001 Jul 15 20:11 Z
19 DLat = D cos C
-----
18 31 N EP lat 2001 Jul 16 0144 Z
18.4 Lm (mid lat)
53 p = D sin C
151 17 W EP lon 2001 Jul 15 20:11 Z
56 W DLo = 56' = p / cos Lm
------
152 13 W EP lon 2001 Jul 16 01:44 Z
Reduce the 0144 Z sight.
40 44.1 Hs Sun LL Jul 16 01:44:36 Z
-2.9 dip
-2.5 IC
14.9 R + SD
-------
40 53.6 Ho
193 30.0 N21 22.8 01 h Sun GHA & dec
208 29.9 N21 22.4 02 h
-------- -------
14 59.9
-.1 -.4 Sun v & d
193 30.0 GHA 01 h
11 09.0 increment 44 m 36 s
-.1 v corr.
--------
204 38.9 GHA at sight time
-152 13.0 assumed lon.
---------
52 25.9 LHA and t at sight time
N21 22.8 dec 01 h
-.3 d corr. 44 m 36 s
--------
N21 22.5 dec at sight time
t 52 26 A 10092
dec N21 22 +B 3093 A 43850
A 13185 -B 17101 B 17101 A 13185
K N32 42 A 26749
L N18 31
K-L 14 11 +B 1344
Hc 40 50 A 18445 -B 12113
Ho 40 54
int 4 toward Z N 77 W A 1072
Update the EP by moving 4 miles toward the body.
18 31 N AP lat
0 01 DLat = 1 min = D cos C
-----
18 32 N corrected EP lat 2001 Jul 16 01:44 Z
18.5 Lm (mid lat)
4 p = D sin C
152 13 W AP lon
4 DLo = 4' = p / cos Lm
------
152 17 W corrected EP lon 2001 Jul 16 01:44 Z
==========
5. Azimuth of Sun = 360 - 77 = 283
6. Fix position Jul 16 01:44 Z = 18 32 N 152 17 W
7. Not practical to compute distance since I didn't carry the DR
forward. I should have done so, and then simply summed the lat and lon
corrections at the time of the second sight.
==========
True course & distance to Hawaiian landfall (mid-lat method):
19 30 N destination lat.
18 32 N running fix 2001 July 16 0145
-----
0 58 DLat (lat. diff.)
154 45 W dest. lon.
152 17 W running fix 2001 Jul 16 0145
------
2 28 DLo = 148 min
19.0 Lm (mid lat)
140 p (departure) = DLo cos Lm
292 C (course) = 360 - arctan(p / DLat)
152 nm Distance = p / (sin C)
True course & distance to Hawaiian landfall (great circle, HO 211)
t 2 28 A 136615
dec N19 30 +B 2565 A 47650
A 139180 -B 36 B 35.5 A 139180
K N19 31 A 47614
L N18 32
K-L 59 +B 6.4
Hc 87 29 A 41.9-B 135744
Z N 68 W A 3436
==========
8. course 292 distance 152 by mid-latitude, 292 / 151 by great circle
==========
The longitude difference to Sydney is small, so I'll use mid latitude
sailing to figure the course and distance.
33 50 S destination lat.
18 32 N lat 2001 July 16 0145 Z
-----
52 22 DLat (lat. diff.) = 3142 min
151 20 W dest. lon.
152 17 W lon 2001 Jul 16 0145 Z
------
57 DLo
13.1 Lm (mid lat) = DLat/4
56 p (departure) = DLo cos Lm
===========
8a.
179 course to Sydney = 180 - arctan (p / DLat)
3142 Distance = DLat / (cos C)
===========
No correct answer was provided for the last question, but my other
results were close enough. I do wish the running fix had been better,
but then I didn't work it the "correct" way.
--
paulhirose@earthlink.net (Paul Hirose)






