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Re: Two Mercury Lunars
From: Andrés Ruiz
Date: 2025 Dec 19, 12:36 +0100
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From: Andrés Ruiz
Date: 2025 Dec 19, 12:36 +0100
Hello Antoine.
I only have time for the first one.
See you.
Lunar sight:
15/12/2025
06:30:00 UT1
LDs = 32.55 = 32º 33.0'
Moon limb = Near
Mercury limb = Center
IC = 0
Altitude sight:
6:30:00
Assumed Position
46º 30.0' N
002º 30.0' W
Moon
Hs = 21º 57.00' = 21.9500 º
Limb = lower
Ref = Sea Horizon
heye = 4.8768 m
IC = 0 '
P = 1008 hPa
T = 8 ºC
Altitude sight:
6:30:00
Assumed Position
46º 30.0' N
002º 30.0' W
Mercury
Hs = 03º 13.00' = 3.2167 º
Limb = center
Ref = Sea Horizon
heye = 4.8768 m
IC = 0 '
P = 1008 hPa
T = 8 ºC
Lunar Distance differential solution
Time by Lunar Distance – observed altitudes
nIter t LDo LDc X[0] Error
0 6.5
1 6.532727439816371 33.362964469564574 33.377024529472585 0.03272743981637115 1.8751441757464746
2 6.532738310550542 33.36295992713067 33.36296459736915 1.0870734171044911E-05 0.0006228471882095195
3 6.5327383110411255 33.362959925621965 33.36295992583272 4.905838972917383E-10 2.8108386811896088E-08
Corrected time = 06:31:57.9 s
15/12/2025
06:30:00 UT1
LDs = 32.55 = 32º 33.0'
Moon limb = Near
Mercury limb = Center
IC = 0
Altitude sight:
6:30:00
Assumed Position
46º 30.0' N
002º 30.0' W
Moon
Hs = 21º 57.00' = 21.9500 º
Limb = lower
Ref = Sea Horizon
heye = 4.8768 m
IC = 0 '
P = 1008 hPa
T = 8 ºC
Altitude sight:
6:30:00
Assumed Position
46º 30.0' N
002º 30.0' W
Mercury
Hs = 03º 13.00' = 3.2167 º
Limb = center
Ref = Sea Horizon
heye = 4.8768 m
IC = 0 '
P = 1008 hPa
T = 8 ºC
Lunar Distance differential solution
Time by Lunar Distance – observed altitudes
nIter t LDo LDc X[0] Error
0 6.5
1 6.532727439816371 33.362964469564574 33.377024529472585 0.03272743981637115 1.8751441757464746
2 6.532738310550542 33.36295992713067 33.36296459736915 1.0870734171044911E-05 0.0006228471882095195
3 6.5327383110411255 33.362959925621965 33.36295992583272 4.905838972917383E-10 2.8108386811896088E-08
Corrected time = 06:31:57.9 s
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