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    Re: Understanding a 1902 Sumner
    From: John D. Howard
    Date: 2017 Jan 20, 21:13 -0800

     David,

    Sorry if I was oblique with my refrence to EOT but looking at a modern table for March the EOT is negative.  Look at the data form - Cor. Eq. T  5 13.3 + A.T.  It seems to me that it shows M.T.G. = EOT + A.T.  So to get apperent time :

    A.T. = M.T.G. - EOT

    I get 1312:17.7 * 15 = 198.07375 degrees GHA sun for the first and 1546:06.7 * 15 = 236.56958

    Working straight St Hiliarie reductions I get:

    Hc = 44.224275   Az = 342          and       Hc = 25.078842   Az = 299

    Drawing the two LOPs they cross at 41 d  16 m  S     174 d  46 m  E

    I did not use modern data but tried to be true to the old information.

    John H.

       
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