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Re: Using the sun's direct and reflected image to determine a sextant's IE
From: Paul Hirose
Date: 2020 Mar 9, 23:03 -0700
From: Paul Hirose
Date: 2020 Mar 9, 23:03 -0700
On 2020-03-09 13:16, Tony Oz wrote: > To obtain the value you should ALWAYS ADD (*algebraically!*) to the H_S do: > -- measure the Sun's width by touching the direct and reflected images right-to-left (or upper-to-lower if you want) and then the left-to-right > -- imagine that the zero on the arc is marked as 360° and therefore if the index is to the left of it - read it as 360°mm', if the index is to the right - read it as 359°nn' > -- calculate 360° - (360°mm' + 359°nn') / 2 The calculation is simplified if you imagine the -1° mark on the limb is 0°. For example, if the sextant reads 1′ high and semidiameter = 15′, the limbs touch at 1°31′ and 0°31′. Index correction = 1° - (1°31′ + 0°31′) / 2 = 1° - 2°02′ / 2 = 1° - 1°01′ = -1′ If it seems more natural, you can reverse the operands in the subtraction. Then the result is index error, which is *subtracted* to get the corrected angle. In fact that's the method I prefer. I also adjust my sextant so an index error determination always produces a small positive result. I believe there's more chance of a blunder if IE is sometimes positive, sometimes negative. There's much confusion about the sense of IC vs. IE. A few years ago I tried to correct someone on this. He replied that many other people do the same thing, and seemed content with his understanding of the matter.