NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: Z or ZN and a couple other fx 260 to excel conversions
From: Guy Schwartz
Date: 2006 May 30, 19:46 -0700
From: Guy Schwartz
Date: 2006 May 30, 19:46 -0700
Bill:
Thank you.
Your answer is the missing piece to my puzzle
I now added a test for sine of LHA >0
8-).
Guy
Hc and Zn by calculation using casio fx 260 calculator
Sin-1Hc = sin(dec) x sin(lat) + cos(dec) x cos(lat) x cos(LHA)
sin(dec) x sin(lat) =
A= 0.207883238 X 0.644790904 0.134041221
cos(dec) x cos(lat) x cos(LHA) =
B= 0.978153648 X 0.764359006 X 0.965389226 0.72178344
Total A + B 0.855824661
Declination, +North -South North Shift Sin-1(Hc) 58.85095947
Latitude, +North -South North 0999 Hc 58? 51.1'
Cos-1 (Zn)= sin(dec) - sin(lat) x sin(Hc) / cos(Hc) x cos(lat)
cos(Hc) x cos(lat) =
A= 0.517255471 X 0.764359006 0.395368878
sin(lat) x sin(Hc) =
B= 0.644790904 X 0.855831045 0.551832073
sin(dec) - B =
C= 0.207883238 - 0.551832073 -0.343948836
C / A =
D= -0.343948836 / 0.395368878 -0.869944134
Shift Cos-1 (Zn) 150.4521481
0999 Zn 209? 32.9'
----- Original Message -----
From: "Bill"
To:
Sent: Monday, May 29, 2006 4:00 PM
Subject: Re: Z or ZN and a couple other fx 260 to excel conversions
> Guy wrote
>
>> I was working out a problem here are the particluars
>> DR 40 deg 9 min N
>> 45 deg W
>> object Regulus
>> Dec 11deg 59. 9 min N
>> LHA 16:25:48
>> HC 58 Deg 20.4 Min
>> Using HO 249 the Z is 150 and the ZN is 210 I also checked with the star
>> section and the ZN was the same.
>> When I did the calculations using
>> Cos rasied to -1 (Zn) = sin (dec) - Sin (lat) x sin (Hc) / cos (Hc) x cos
>> (lat)
>>
>> The answer came out to 148 deg 11.4 min which is close to the 150 Z
>> however I
>> though that formula gave me the Zn?
>
> Yes and no, it is situational as the HC can be the same at some point
> before
> and some point after noon (using the sun as an example). With the sun LAN
> (local area noon, sun at its highest point) is also the upper meridian
> passage. For any body, LHA = 0 for upper meridian passage. To extract Zn
> from Z, determine whether the body is rising (pre meridian passage) or
> setting (post meridian passage.
>
> If rising, Zn = Z. If setting, Zn = 360 - Z.
>
> When in doubt, if the sine of LHA is positive, Zn = 360 - Z. When the
> sine
> of LHA is negative, Zn = Z.
>
> My memory device is "plus minus." When the sign of sine LHA is PLUS, Zn =
> 360 MINUS Z.
>
> Bill
>
>
> --
> No virus found in this incoming message.
> Checked by AVG Free Edition.
> Version: 7.1.394 / Virus Database: 268.7.4/351 - Release Date: 5/29/2006
>
>






