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    Re: Z or ZN and a couple other fx 260 to excel conversions
    From: Guy Schwartz
    Date: 2006 May 30, 19:46 -0700

    Bill:
    Thank you.
    Your answer is the missing piece to my puzzle
    I now added a test for sine of LHA >0
    8-).
    Guy
          Hc and Zn by calculation using casio fx 260 calculator
         Sin-1Hc = sin(dec) x sin(lat) + cos(dec) x cos(lat) x cos(LHA)
    
           sin(dec) x sin(lat) =
          A= 0.207883238 X 0.644790904 0.134041221
         cos(dec) x cos(lat) x cos(LHA) =
          B= 0.978153648 X 0.764359006 X 0.965389226 0.72178344
             Total A + B 0.855824661
          Declination,  +North -South  North Shift Sin-1(Hc)  58.85095947
          Latitude,  +North -South  North 0999 Hc 58? 51.1'
    
         Cos-1 (Zn)= sin(dec) - sin(lat) x sin(Hc) / cos(Hc) x cos(lat)
           cos(Hc) x cos(lat) =
          A= 0.517255471 X 0.764359006 0.395368878
           sin(lat) x sin(Hc) =
          B= 0.644790904 X 0.855831045 0.551832073
           sin(dec) - B =
          C= 0.207883238 - 0.551832073 -0.343948836
           C / A =
          D= -0.343948836 / 0.395368878 -0.869944134
             Shift Cos-1 (Zn) 150.4521481
             0999 Zn 209? 32.9'
    
    ----- Original Message -----
    From: "Bill" 
    To: 
    Sent: Monday, May 29, 2006 4:00 PM
    Subject: Re: Z or ZN and a couple other fx 260 to excel conversions
    
    
    > Guy wrote
    >
    >> I was working out a problem here are the particluars
    >> DR 40 deg 9 min N
    >> 45 deg W
    >> object Regulus
    >> Dec 11deg 59. 9 min N
    >> LHA 16:25:48
    >> HC 58 Deg 20.4 Min
    >> Using HO 249 the Z is 150 and the ZN is 210 I also checked with the star
    >> section and the ZN was the same.
    >> When I did the calculations using
    >> Cos rasied to -1 (Zn) = sin (dec) - Sin (lat) x sin (Hc) / cos (Hc) x cos
    >> (lat)
    >>
    >> The answer came out to 148 deg 11.4 min which is close to the 150 Z
    >> however I
    >> though that formula gave me the Zn?
    >
    > Yes and no, it is situational as the HC can be the same at some point
    > before
    > and some point after noon (using the sun as an example). With the sun LAN
    > (local area noon, sun at its highest point) is also the upper meridian
    > passage. For any body, LHA = 0 for upper meridian passage.  To extract Zn
    > from Z,  determine whether the body is rising (pre meridian passage) or
    > setting (post meridian passage.
    >
    > If rising, Zn = Z.  If setting, Zn = 360 - Z.
    >
    > When in doubt, if the sine of LHA is positive, Zn = 360 - Z.  When the
    > sine
    > of LHA is negative, Zn = Z.
    >
    > My memory device is "plus minus."  When the sign of sine LHA is PLUS, Zn =
    > 360 MINUS Z.
    >
    > Bill
    >
    >
    > --
    > No virus found in this incoming message.
    > Checked by AVG Free Edition.
    > Version: 7.1.394 / Virus Database: 268.7.4/351 - Release Date: 5/29/2006
    >
    >
    
    
    

       
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