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    Re: A triangle on the equator
    From: Martin Caminos
    Date: 2025 Oct 6, 21:18 -0700

    Hello Frank,

    I enjoyed the challenge !.

    Here goes my calculations:

    Due to the short distance between points A and C, there will be not much difference between Ortodromic and Loxodromic navigation.

    For Ortodromic navigaction (great circle) the initial angle (this is importan to mention) would be 53° 7.8' (which is the angle you would measure with the sextant), and the distance would be 10 NM.

    For Loxodromin navigation the constant angle would be 53° 18.6', and the distance would be 10.04 NM.

    Also, it would be almost a 3:4:5 (spherical) triangle with the following distances:

    A-B: 6 NM

    B-C: 7.99 NM

    A-C: 10 nm

    Looking forward to hearing other comments.

    Thanks !

       
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