NavList:
A Community Devoted to the Preservation and Practice of Celestial Navigation and Other Methods of Traditional Wayfinding
Re: A triangle on the equator
From: Martin Caminos
Date: 2025 Oct 6, 21:18 -0700
From: Martin Caminos
Date: 2025 Oct 6, 21:18 -0700
Hello Frank,
I enjoyed the challenge !.
Here goes my calculations:
Due to the short distance between points A and C, there will be not much difference between Ortodromic and Loxodromic navigation.
For Ortodromic navigaction (great circle) the initial angle (this is importan to mention) would be 53° 7.8' (which is the angle you would measure with the sextant), and the distance would be 10 NM.
For Loxodromin navigation the constant angle would be 53° 18.6', and the distance would be 10.04 NM.
Also, it would be almost a 3:4:5 (spherical) triangle with the following distances:
A-B: 6 NM
B-C: 7.99 NM
A-C: 10 nm
Looking forward to hearing other comments.
Thanks !






