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Re: Formula to determine GHA of Sun?
From: Bill B
Date: 2014 Sep 13, 15:03 -0400
From: Bill B
Date: 2014 Sep 13, 15:03 -0400
> > Thank you for the method. I read Henry's comments on the Time Sight > method but I know nothing about it other than that. Can you direct me to > a clear exposition of it? Following is a historical explanation from frank Reed: http://fer3.com/arc/m2.aspx/Time-sight-primer-FrankReed-dec-2012-g21555 Another of Franks posts: http://fer3.com/arc/m2.aspx/Time-sights-for-Jim-T-FrankReed-sep-2004-w17728 There was also, if I recall, a post from Frank on the "reverse" time sight. That is, if your know your exact location you can use a derivative of the time sight to find the time. Can't locate it at the moment. Another note on the time sight: Don't take my ramblings as gospel. I hope I have it right, and that the more learned with better memories will join in and clear up my mistakes. If memory serves the angle the formula gives is not always an LHA-- strictly speaking. It is the angle between the observers meridian and the body, but can be on the "wrong" side observer's meridian so may not strictly adhere to the definition of LHA. Some inspection/common-sense test and/or sketch may be needed. At the moment I'm eyeball deep in house restoration projects, and my main desktop work computer melted down (power supply and mother board) so I'm in recovery mode and don't have handy access to my files, so the above is the best I can do for now.
