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Re: Real accuracy of the method of lunar distances
From: Jan Kalivoda
Date: 2004 Jan 1, 02:33 +0100
From: Jan Kalivoda
Date: 2004 Jan 1, 02:33 +0100
Dear Fred, I agree with all in your last message, with the exception of the last but one paragraph, which was the most important, of course. I repeat only this passage: >You appeared to be constructing confidence intervals based upon the t statistic. The test statistic in this case would be t = (deviation from chronometer time) / (standard deviation/square root of number of observations). The "(standard deviation/square root of number of observations)" seems to be the standard error of the (any) mean. But what is meant by "(deviation from chronometer time)"? Is it an error of one observation from six in each subset or an average error of a subset (more probably)? And what sense has the whole fraction, giving the value "t"? Sorry, I didn't find it in my manuals of mathematics during very short searches at the beginning of the New Year in Europe. Thank you for an explanation. Jan Kalivoda